2x^2-50x+128=0

Solution for 2x^2-50x+128=0 equation:

2x^2-50x+128=0

a = 2; b = -50; c = +128;
Δ = b2-4ac
Δ = -502-4·2·128
Δ = 1476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1476}=\sqrt{36*41}=\sqrt{36}*\sqrt{41}=6\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-6\sqrt{41}}{2*2}=\frac{50-6\sqrt{41}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+6\sqrt{41}}{2*2}=\frac{50+6\sqrt{41}}{4}
$